menghitung batas atas bawah dan tengah pada garis bidik yalon untuk ilmu ukur tanah

Soal

        1,765 m                                                                 1,636    1,388

         1,400 m                    B ?m     1,933m                1,400    1,050                     1,999 m                                              

        A ?  m                        1,855     C ? m                       D ? m       E ?  m                  1,777 m   1,800 m               1,650 m    

                                          1,366    1,444 m                                                                   F  ?m

Ditanya :

1. Tentukanlah batas atas,bawah dan tengah  pada masing-masing yalon!

2. Jarak alat masing-masing dari muka maupun belakang!

3. Beda tinggi A ke B!

Penyelesaian :

1.      Rumus Umum :     BT =

A.    2BT = BA + BB                                       D. 2BT = BA + BB

2(1,400 )    = 1,765  + BB                                         2(1,400)      = 1,636 + BB

2,8             = 1,765 + BB                               2,8              = 1,636 + BB

2,8-1,765   = BB                                            2,8-1,636    = BB                               

BB             = 1,035 m                                     BB              = 1,164 m

B.     2BT = BA + BB                                       E. 2BT = BA + BB

2(1,855)     = BA + 1,366                               2(1,050)      = 1,388 + BB

3,71           = BA + 1,366                               2,1              = 1,388 + BB

3,71-1,366 = BA                                            2,1-1,388   = BB

BA                        = 2,344 m                                     BB              = 0,712 m

                             

C.     2BT = BA + BB                                       F. 2BT = BA + BB

2BT           = 1,933 + 1,444                           2(1,777)       = 1,999 + BB

2BT           = 3,377                                        3,554           = 1,999 + BB

BT             = 3,377 / 2                                   3,554-1,999 = BB

BT             = 1,6885 m                                  BB               = 1,555 m

2.      Jarak = (Ba – Bb) x 100

db 1     = (Ba – Bb) x 100                              db 3     = (Ba – Bb) x 100

            =  (1,765 – 1,035) x 100                                 = (1,388-0,712) x100

            =  0,73 x 100                                                   = (0,676) x 100

            = 73                                                                 = 67,6

dm 1    = (Ba – Bb) x 100                               dm 3    = (Ba - Bb) x 100

            = (2,344 – 1,366) x 100                                  = (1,999 -1,555) x 100

            = 0,978 x 100                                                  = 0,444 x100

            = 97,8                                                              = 44,4

db 2     = (Ba – Bb) x 100

            = (1,933 – 1,444) x 100

            = 0,489 x 100

            = 48,9

dm 2    = (Ba – Bb) x 100

            = (1,636-1,164) x 100

            = 0,472 x 100

            = 47,2                                     

                                                                       

     ,

                            =

           = (73 + 48,9 + 67,6)                         45

           = 189,5                                            189,5 + db4   = 239,45      189,4+dm4  =239,45

               db4                = 49,95            dm4         = 50,05

 = (97,8 + 47,2 + 44,4)

 = 189,4

3.      Beda tinggi titik A dengan titik B

 

A dengan titik I   (SLAG 1)                                       1,400  - 1,855 = 0,455 (turun)

I   dengan titik II (SLAG 2)                                                   1,6885 –1,400 =  0,2885 (naik)

II dengan titik III(SLAG 3)                                                   1,050  - 1,777 = 0,727 (turun)

III dengan titik B (SLAG 4)                                                  1,800  - 1,650 = 0,15 (naik)